Skip to main content

Backtracking - Question 2

 Leetcode 52. N-Queens II

The n-queens puzzle is the problem of placing n queens on an n x n chessboard such that no two queens attack each other.

Given an integer n, return the number of distinct solutions to the n-queens puzzle.

Constraints:

1 <= n <= 9


Analysis:

The answer to the previous question can be used directly: just need to return the size of it.

For the coding part, we do not need to record the actual solution, so simplification of code can be done.

The idea is the same as the previous question: try to place a queen for each row. 

And we just removed the previous vectors to record the solution. Instead, we just count the number of solutions.


See the code below:


class Solution {
public:
    int totalNQueens(int n) {
        ps.resize(n);
        fill(ps.begin(), ps.end(), -1);
        bt(0, 0);
        return res;
    }
private:
    int res = 0;
    vector<int> ps;
    void bt(int r, int ct) {
        if(r == ps.size()) {
            if(ct == ps.size()) ++res;
            return;
        }
        for(int i=0; i<ps.size(); ++i) {
            if(isValid(r, i)) {
                ps[r] = i; // make a trial
                bt(r + 1, ct + 1);
                ps[r] = -1; // step back (or backtrack)
            }
        }
    }
    bool isValid(int id, int val) {
        for(int i=0; i<id; ++i) {
            if(ps[i] == -1) continue;
            if(ps[i] == val || abs(id - i) == abs(val - ps[i])) return false;
        }
        return true;
    }
};

 

Upper Layer

Comments

Popular posts from this blog

Binary Search - Example

Binary Search - Example Leetcode 35  Search Insert Position Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You must write an algorithm with O(log n) runtime complexity. Constraints: 1 <= nums.length <= 10^4 -10^4 <= nums[i] <= 10^4 nums contains distinct values sorted in ascending order. -10^4 <= target <= 10^4 Analysis: The array is sorted, so we just need to run a routine binary search. Make a guest first, then based on the guessed result, we can adjust the search range. See the code below: class Solution { public: int searchInsert(vector<int>& nums, int target) { int left = 0, right = nums.size(); while(left < right) { int mid = left + (right - left) / 2; if(nums[mid] < target) left = mid + 1; else right = mid; } return left; } }; If you know t...

Graph Question - Hard Level - Question 1

2246. Longest Path With Different Adjacent Characters You are given a tree (i.e. a connected, undirected graph that has no cycles) rooted at node 0 consisting of n nodes numbered from 0 to n - 1. The tree is represented by a 0-indexed array parent of size n, where parent[i] is the parent of node i. Since node 0 is the root, parent[0] == -1. You are also given a string s of length n, where s[i] is the character assigned to node i. Return the length of the longest path in the tree such that no pair of adjacent nodes on the path have the same character assigned to them. Constraints: n == parent.length == s.length 1 <= n <= 10^5 0 <= parent[i] <= n - 1 for all i >= 1 parent[0] == -1 parent represents a valid tree. s consists of only lowercase English letters. Analysis For this question, we need to construct a graph, or more specifically, a n-nary tree. How to construct the graph/tree? What we only know is the parent array. So we need to go through the parent array and constr...